MATH SOLVE

3 months ago

Q:
# A solution is heated from 0°C to 100°C. Between 0°C and 50°C, the rate of temperature increase is 1.5°C/min. Between 50°C and 100°C, the rate of temperature increase is 0.4°C/min. What is the average rate of temperature increase during the entire heating process? Round to the nearest tenth.

Accepted Solution

A:

Answer: 0.6 °C/minStep-by-step explanation:The relationship between rates and movement is ... time = distance/speedHere, the "distance" is measured in °C, and the "speed" is the rate of change of temperature.For the first half of the heating, the time required is ... (50°C -0°C)/(1.5 °C/min) = 50/(3/2) min = 100/3 minFor the second half of the heating, the time required is ... (100°C -50°C)/(4/10 °C/min) = 50/(4/10) = 125 minThen the total time is ... ((100/3) +125) min = (475/3) minAnd the average rate of temperature increase is ... total temperature change / total time = (100°C -0°C)/(475/3 min) = 300/475 °C/min = 12/19 °C/min ≈ 0.6 °C/min